![Integrate log x/(1+log x)^2 dx || Integration sn dey class 12 Solutions | Indefinite integral - 5 - YouTube Integrate log x/(1+log x)^2 dx || Integration sn dey class 12 Solutions | Indefinite integral - 5 - YouTube](https://i.ytimg.com/vi/uj9UyCWyszE/maxresdefault.jpg)
Integrate log x/(1+log x)^2 dx || Integration sn dey class 12 Solutions | Indefinite integral - 5 - YouTube
![Equazioni esponenziali e logaritmiche: \frac{{ \log{{\left({x}-{1}\right)}}}}{ \log{{\left({x}^{3}-{8}{x}+{5}\right)}}}=\frac{1}{{3}} Equazioni esponenziali e logaritmiche: \frac{{ \log{{\left({x}-{1}\right)}}}}{ \log{{\left({x}^{3}-{8}{x}+{5}\right)}}}=\frac{1}{{3}}](https://www.skuola.net/news_foto/2017/10/equ_log_e1.jpg)
Equazioni esponenziali e logaritmiche: \frac{{ \log{{\left({x}-{1}\right)}}}}{ \log{{\left({x}^{3}-{8}{x}+{5}\right)}}}=\frac{1}{{3}}
Find the general solution of the differential equation dy/dx = log(x + 1). - Sarthaks eConnect | Largest Online Education Community
![Equazioni esponenziali e logaritmiche: \frac{6}{{{\left( \log{{x }}\right)}^{2}-{1}}}+\frac{3}{{ \log{{x}}+{1}}}=\frac{{ \log{{x}}+{1}}}{{ \ log{{x}}-{1}}} Equazioni esponenziali e logaritmiche: \frac{6}{{{\left( \log{{x }}\right)}^{2}-{1}}}+\frac{3}{{ \log{{x}}+{1}}}=\frac{{ \log{{x}}+{1}}}{{ \ log{{x}}-{1}}}](https://www.skuola.net/news_foto/2017/10/equ_log_e2.jpg)
Equazioni esponenziali e logaritmiche: \frac{6}{{{\left( \log{{x }}\right)}^{2}-{1}}}+\frac{3}{{ \log{{x}}+{1}}}=\frac{{ \log{{x}}+{1}}}{{ \ log{{x}}-{1}}}
![logarithms - Solving $9^{1+\log x} - 3^{1+\log x} - 210 = 0$ where base of log is $3$ for $x$ - Mathematics Stack Exchange logarithms - Solving $9^{1+\log x} - 3^{1+\log x} - 210 = 0$ where base of log is $3$ for $x$ - Mathematics Stack Exchange](https://i.stack.imgur.com/OR8Rm.jpg)